Coaxial System of Circles

Find the limiting points of the co-axial system of circles $x^2+y^2+2\lambda x+16=0$.

Find the limiting points of the co-axial system of circles $x^2+y^2+2\lambda x+4=0$.

Cotyledons are also called-

If $x^2+y^2-4x-2y+5=0$ and $x^2+y^2-6x-4y-3=0$ are members of a coaxial system of circles then centre of a point circle in the system is

The coaxial system of circles given by $x^2+y^2+2gx+c=0$ for $c<0$ respects

The limiting points of coaxial-system determined by the circles $x^2+y^2+5x+y+4=0$ and $x^2+y^2+10x-4y-1=0$ are

The coaxial system of circles given by $x^2+y^2+2gx+c=0$ for $c<0$ represents

The limiting points of the coaxial system of circles $x^2+y^2+2\lambda y+4=0$ are

The coaxial system of circles given by $x^2+y^2+2gx+c=0$ for $c<0$ represents

The coaxial system of circles given by $x^2+y^2+2gx+c=0$ for $c<0$ is/are

The coaxial system of circles given by $x^2+y^2+2gx+c=0$ for $c < 0$represents